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| Mathdisplay |
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\triangle f =\frac{1}{R^2 \ cos^2\phi}\frac{\partial^2 f}{\partial \lambda^2} + \frac{1}{R^2}\frac{\partial^2 f}{\partial \phi^2} - \frac{1}{R^2}tan\phi\frac{\partial f}{\partial \lambdaphi} |
where
- R is the radius of the Earth
- φ is the latitude
- λ is the longitude.
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