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There is a consequence of the 0-value problem treatment over dry or very dry areas (described above), as some or all of the low anomaly signals will not be impossible to occur. Please consider some of these idealised examples, with a fixed portion of the ensemble members being 0 and the rest having a simple average rank, in order to simplify the rank-mean and dominant anomaly category computation:

No-1 example: The

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1-10 climate percentiles are 0, so the average rank of the

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0 ensemble members will always be around 5.5 with the evenly distributed rank representation:

Number of 0 membersNumber of non-0 membersAverage rank of 0 membersAverage rank of non-0 membersRank-meanDominant anomaly categoryComment
051NA (no member to rank)11 (the lowest possible rank for a non-zero member if 1-10 percentiles in the climatology are 0)(0 * 5.5 + 51 * 11)/51 = 11Low (10-25%)Lowest possible overall rank (and dominant anomaly category)
051NA20(0 * 5.5 + 51 * 20)/51 = 20Low (10-25%)
051NA50(0 * 5.5 + 51 * 50)/51 = 50Near normal (40-60%)
051NA70(0 * 5.5 + 51 * 70)/51 = 70Bit high (60-75%)
051NA100(0 * 5.5 + 51 * 100)/51 = 100Extreme high (90%<)







11405.511(11 * 5.5 + 40 * 11)/51 = 9.81Extreme low (<10%)
11405.520(11 * 5.5 + 40 * 20)/51 = 16.87Low (10-25%)
11405.550(11 * 5.5 + 40 * 50)/51 = 40.40Near normal (40-60%)
11405.570(11 * 5.5 + 40 * 70)/51 = 56.08Near normal (40-60%)
11405.5100(11 * 5.5 + 40 * 100)/51 = 79.61High (75-90%)







21305.511

(21 * 5.5 + 30 * 11)/51 = 8.73

Extreme low (<10%)
21305.520(21 * 5.5 + 30 * 20)/51 = 14.02Low (10-25%)
21305.550(21 * 5.5 + 30 * 50)/51 = 31.67Bit low (25-40%)
21305.570(21 * 5.5 + 30 * 70)/51 = 43.44Near normal (40-60%)
21305.5100(21 * 5.5 + 30 * 50)/51 = 61.08Bit high (60-75%)







36155.511

(36 * 5.5 + 15 * 11)/51 = 7.11

Extreme low (<10%)
36155.520(36 * 5.5 + 15 * 20)/51 = 9.76Extreme low (<10%)
36155.550(36 * 5.5 + 15 * 50)/51 = 18.58Low (10-25%)
36155.570(36 * 5.5 + 15 * 70)/51 = 24.47Low (10-25%)
36155.5100(36 * 5.5 + 15 * 50)/51 = 33.29Bit low (25-40%)







5105.5NA (no member to rank)

(51 * 5.5 + 0)/51 = 5.5

Extreme low (<10%)

No-2 example: The 1-30 climate percentiles are 0, so the average rank of the 0 ensemble members will always be around 15.5 with the evenly distributed rank representation:

Number of 0 membersNumber of non-0 membersAverage rank of 0 membersAverage rank of non-0 membersRank-meanDominant anomaly categoryComment
051NA (no member to rank)31 (the lowest possible rank for a non-zero member if 1-30 percentiles in the climatology are 0)(0 * 15.5 + 51 * 31)/51 = 31Bit low (25-40%)Lowest possible rank (and dominant anomaly category)
051NA50(0 * 15.5 + 51 * 50)/51 = 50Near normal (40-60%)
051NA70(0 * 15.5 + 51 * 70)/51 = 70Bit high (60-75%)
051NA100(0 * 15.5 + 51 * 100)/51 = 100Extreme high (90%<)







11405.511(11 * 15.5 + 40 * 31)/51 = 27.65Bit low (25-40%)
11405.550(11 * 15.5 + 40 * 50)/51 = 42.55Near normal (40-60%)
11405.570(11 * 15.5 + 40 * 70)/51 = 58.24Near normal (40-60%)
11405.5100(11 * 15.5 + 40 * 100)/51 = 81.77High (75-90%)







21305.511

(21 * 15.5 + 30 * 31)/51 = 24.61

Low (10-25%)
21305.550(21 * 15.5 + 30 * 50)/51 = 35.79Bit low (25-40%)
21305.570(21 * 15.5 + 30 * 70)/51 = 47.55Near normal (40-60%)
21305.5100

(21 * 15.5 + 30 * 100)/51 = 65.20

Bit high (60-75%)







36155.511

(36 * 15.5 + 15 * 11)/51 = 20.05

Low (10-25%)
36155.550(36 * 15.5 + 15 * 50)/51 = 25.64Bit low (25-40%)
36155.570(36 * 15.5 + 15 * 70)/51 = 31.52Bit low (25-40%)
36155.5100(36 * 15.5 + 15 * 100)/51 = 40.35Near normal (40-60%)







5105.5NA (no member to rank)

(51 * 15.5 + 0)/51 = 15.5

Low (10-25%)




  • If all ensemble members are 0, then the ranks will spread evenly from 1 to 10 and the rank-mean will be around 5.5, so in the Extreme low category.

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