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changes.mady.by.user Unknown User (ma0)

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changes.mady.by.user Unknown User (ma0)

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Code Block
languagepy
from ecflow import *
defs = Defs() + Suite("s1")
defs.s1 += [ Task("t1"),Task("t2"),Task("t3"),Task("t4") ]
defs.s1.t2 += Trigger( "t1 == complete" )
defs.s1.t3 += Trigger( "t2 == complete" )
defs.s1.t4 += Trigger( "t3 == complete" )



Code Block
languagepy
from ecflow import *
defs = Defs() + Suite("s1")
defs.s1 += [ Task("t1"),Task("t2"),Task("t3"),Task("t4") ]
defs.s1.t2 += Trigger( ["t1"] ) 
defs.s1.t3 += Trigger( ["t2"] )
defs.s1.t4 += Trigger( ["t3"] )



Code Block
languagepy
from ecflow import *
defs = Defs() + Suite("s1")
defs.s1 >> Task("t1") >> Task("t2") >> Task("t3") >> Task("t4")
# >> relies on the leading node to be a Family or Suite


Reverse Chaining

It is also possible to << to reverse chain task.

The following suites are identical:


Code Block
languagepy
defs = Defs() + Suite("s1")
defs.s1 += [ Task("t1"),Task("t2"),Task("t3"),Task("t4") ]
defs.s1.t1 += Trigger( "t2 == complete" )
defs.s1.t2 += Trigger( "t3 == complete" )
defs.s1.t3 += Trigger( "t4 == complete" )



Code Block
languagepy
defs = Defs() + Suite("s1")
defs.s1 << Task("t1") << Task("t2") << Task("t3") << Task("t4")
# << relies on the leading node to be a Suite or Family